Dotted Tie Pattern #314

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Dotted Tie Pattern #314

Materials: J. & P. Coats Knit-Cro-Sheen or Clark's O.N.T. Cronita, 2 balls of color 84 Beige and 1 ball of color 126 Spanish Red. Milward's steel crochet hook No. 8.

Work tightly. All clusters are made in Red and all s c's are made in Beige, carrying along Red and working over it as explained later.

With Beige ch 5, join with a sl st. 1st row: 3 s c into ring. Ch 1, turn. 2nd row: 2 s c in first s c. 1 s c in next s c, 2 s c in last s c, ch 1, turn. 3rd row: 2 s c in first s c, 1 s c in each of next 3 s c, 2 s c in last s c, ch 1, turn. 4th row: 2 s c in first s c, 1 s c in each of next 5 s c, 2 s c in last s c, ch 1, turn. 5th row: Attach Spanish Red, with Beige work over previous row, carrying along Spanish Red and working over it so that after this row is worked, Red will be invisible. Make 2 s c in 1st s c, 1 s c in each of 3 s c, drop Beige (to back of work), pick up red and make a 3-d c cluster in next s c at the base of previous row, as follows: Make 3 d c in same st always holding the last loop of each d c on hook; then, thread over hook and take off all remaining loops. A tight ch st should then be made to fasten the cluster. (All clusters are made by inserting hook at the base of 1 row previous.) Drop red (to back of work) and with Beige (carrying along red and working over it) make 1 s c in each of 3 s c, 2 s c in last sc. Ch 1, turn. 6th and 7th rows: (With Beige, carrying along red and working over it.) S c in each st of previous row, making 2 s c in 1st s c and 2 s c in last s c. 8th row: With Beige (working over red as before—make all s c with Beige carrying along red and working over it). Make 2 s c in first s c, 1 s c in each of 3 s c, 1 cluster, s c in each of 5 s c, 1 cluster, s c in each of 3 s c, 2 s c in last s c. Repeat 6th, 7th and 8th rows until 8 clusters are in a row, taking care to have clusters come in exact center of space of clusters of previous cluster row. Hereafter, work without increasing, having 8 clusters in one cluster row and 7 clusters in next cluster row alternately, until 16 cluster rows are made in all, decreasing 1st at beginning and end of 14th and 16th cluster rows. (To decrease, work 2 s c together 8 clusters in 16th cluster row.) Then decrease 1 s c at beginning and 1 s c at end of next row and every 12th row for 3 times in all, having 7 and 6 cluster rows alternately until 28 cluster rows are made in all (6 clusters in 28th cluster row). Then decrease 1 s c at beginning and end of every 12th row, twice, having 5 and 6 cluster rows alternately, until 36 cluster rows are made in all (6 clusters in 36th cluster row).

Decrease every 10th row, having 5 and 4 cluster rows alternately, until 47 cluster rows are made in all (5 clusters in 47th cluster row). Decrease every 12th row, having 4 and 3 cluster rows alternately, until 56 cluster rows are made in all (4 clusters on 56th cluster row). Decrease on every 7th row, having 3 and 2 cluster rows alternately until 67 cluster rows are made in all (3 clusters on 67th cluster row). Hereafter work without decreasing. There will be 2 and 1 cluster rows alternately until 106 cluster rows are made in all (2 clusters in 106th cluster row). Then begin to increase (to increase make 2 s c in 1 s c) l s c at beginning and at end of every 9th row, having 3 and 2 cluster rows alternately until 117 cluster rows are made in all (3 clusters on 117th cluster row).

Increase every 9th row, having 4 and 3 cluster rows alternately until 126 cluster rows are made in all (4 clusters on 126th cluster row). Increase on next 17 rows twice, having 5 and 4 cluster rows alternately until 137 cluster rows are made in all. (5 cluster rows on 137th cluster row). Hereafter decrease 1 st at beginning and at end of every row having 4, 3, 2 and 1 cluster rows. Then, finish point as for beginning.